110m^2=1/2B*10M=

Solution for 110m^2=1/2B*10M= equation:

110m^2=1/2*10=

We move all terms to the left:

110m^2-(1/2*10)=0

We add all the numbers together, and all the variables

110m^2-(+1/2*10)=0

We get rid of parentheses

110m^2-1/2*10=0

We multiply all the terms by the denominator


110m^2*2*10-1=0

Wy multiply elements

2200m^2*1-1=0

Wy multiply elements

2200m^2-1=0

a = 2200; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·2200·(-1)
Δ = 8800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8800}=\sqrt{400*22}=\sqrt{400}*\sqrt{22}=20\sqrt{22}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{22}}{2*2200}=\frac{0-20\sqrt{22}}{4400}
=-\frac{20\sqrt{22}}{4400}
=-\frac{\sqrt{22}}{220}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{22}}{2*2200}=\frac{0+20\sqrt{22}}{4400}
=\frac{20\sqrt{22}}{4400}
=\frac{\sqrt{22}}{220}
$